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23.(1)B(1分)D(1分)F(1分)(2)电路图如图所示(2分)(3)实物图如图所示(2分)应、(4)增大(1分)(5)0.10W~0.12W(2分)解析:(1)小灯泡额定电压为2.5V,电压表选V1;小灯泡额定电流为0.3A,电流表选A1;根据题意,要求小灯泡两端电压从零开始变化,故滑动变阻器采用分压式接法,应选用总阻值较小的R1(2)滑动变阻器采用分压式接法,同时灯泡的电阻较小,为了减小误差,故只能采用电流表外接法,电路图如答案图所示(3)依据电路原理图,将0.30A实物连线,如答案图所020示(4)从绘制出的伏安特1.0203.0性曲线的弯曲情况可以看出,随着温度的升高,小灯泡灯丝的电阻率增大(5)在小灯泡的伏安特性曲线中,作出电源的I一U图,如图所示,此时小灯泡实际消耗的功率为P=IU=0.184×0.58W=0.11w
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