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22.【解析】(I由(t为参数),消去参数t,可得x+3y-1=0.p=4cos0,∴p2=4pcos,即x2+y2-4x∴曲线的直角坐标方程为(x-2)2+y2=4.,(Ⅱ)把代入x2+y2-4x=0,得12+3t-3=0设A,B两点对应的参数分别为t1,t2,则t1+t2=-3,t1t2=-3因为直线l经过点P(1,0),则|AB|=||PB|-|PA2-t1(t1+t2)2-4tt2=√15
书面表达Onepossibleversion:NOTICEAsportsmeetingwillbeheldintheplaygroundofourschoolfromnextThursdaytoFridayAsyouknow,thepressureofstudyisveryheavynow,especiallyforthosesenior3.Sothepurposeofthesportsmeetingistoleteverystudentgetrelaxed,asaresultofwhichwestudentscanlivehappilyandhealthilyEveryoneiswelcometotakepartinit.Thosewhoperformexcellentlyatthesportsmeetingwillgetprizes.Butdon'ttaketheresultssoserouslybecausetakingpartismoreimportantthantheresult.Goodlucktoeveryone!
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